First slide
Work done by Diff type of forces
Question

A spring of force constant 'k' is stretched by a  small length 'x'. The work done in stretching it further by a small length 'y' is,
 

Easy
Solution

\large w = \frac{1}{2}K({(x + y)^2} - {x^2})
\large w = \frac{1}{2}K({x^2} + {y^2} + 2xy - {x^2}) = \frac{1}{2}Ky(2x + y)

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