First slide
Work
Question

A spring of force constant 800 N/m  has an extension of 5 cm.  The work done in extending it from 5cm to 15cm is,

Moderate
Solution

work done in extending the spring is W  =    12K(x22x12)                given    x2  =   15×102m  and           x1  =   5×102m force constant k=800N/m substitute given values in above equation of work W=    12 (800){(15x10 -2)2 (5x10-2)2}  work done =8 joule

 

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