A spring has a force constant k and a mass m is suspended from it. The spring is cut in half and the same mass is suspended from one of the halves. If the frequency of oscillation in the first case is α, then the frequency in the second case will be
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a
2α
b
α
c
α/2
d
α2
answer is D.
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Detailed Solution
T=2πmk or α=12πkm When the spring is cut into trvo equal parts, each part has a spring coustant 2 K. Hence α1=12π2km =212πkm=2⋅α