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Question

A spring 40 mm long is stretched by the application of a force. If 10 N force required to stretch the spring through 1 mm, then work done (in J) in stretching the spring through 40 mm is

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Solution

Here $k = \frac{F}{x} = \frac{10}{1 \times 10^{- 3}} = 10^{4} N / m$
$W = \frac{1}{2} {kx}^{2} = \frac{1}{2} \times 10^{4} \times {(40 \times 10^{- 3})}^{2} = 8 J$

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