A spring of spring constant K is cut into n equal parts, out of which r parts are placed in parallel and connected with mass m as shown in figure. The time period of oscillatory motion of mass m is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
T = 2πmnrK
b
T = 2πnrmK
c
T = 2πrmnK
d
T =2πnmrK
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
K.l = k'×ln = constantnew spring constant for each part is K' = nKNow r part are taken in parallelso Keq = nrkTime period = 2πmKeq = 2πmnrK