First slide
Work
Question

A spring of spring constant  5×103 N/m  &  stretched initially by 5 cm from the unstretched position.  Then work done required to stretch it further by another 5cm is

Moderate
Solution

work done to stretch spring is W  =    12K  (x22x12) given spring constant is K=5 x103N/m; x2=10cm=10x10-2m;x1=5cm=5x10-2m W  =    12×5×103(10252)×104 W  =    5×1032×0.0075 W  =    18.75 joule 

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