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A spring of spring constant 5 × 103 N/m is stretched initially by 5 cm from the unstretched position. Then the work required to stretch it further by another 5 cm is (in J)

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answer is 18.75.

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Detailed Solution

W=12k(x22−x12)=12×5×103(102−52)×10−4=18.75 J

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A spring of spring constant 5 × 103 N/m is stretched initially by 5 cm from the unstretched position. Then the work required to stretch it further by another 5 cm is (in J)