First slide
Work
Question

A spring of spring constant 5×103N/m is stretched initially by 5cm from the unstretched position. The work required to further stretch the spring by another 5cm is

Moderate
Solution

         W=UfUi  work done= difference in PE of spring W=12K(Xf2Xi2)x=distancefromunstretchedposition;Xf =10cm=0.1m;;Xi =0.05m;K=5×103N/mW=12×5×103[0.120.052]Work required to further stretch the spring=18.75J

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