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Questions  

 A spring of spring constant 5x103 N/m  is stretched initially by 5 cm from the unscratched position. Then the work required to stretch it further by another 5 cm is

a
6⋅25N−m
b
12⋅50N−m
c
18 . 75 N-m
d
25 '00 N-m

detailed solution

Correct option is C

for a spring .U =12kx12where x1 =5 cmWhen the spring is further stretched by 5 cm, thenU′=12kx22Now W=U′−U=12kx22−x12=125×10310×10−22−5×10−22 =18.75Nm

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