Questions
A spring of spring constant 5 x 103 N/m is stretched initially by 5 cm from the upstretched position. Then work required to stretch it further by another 5 cm is :
detailed solution
Correct option is B
Work done = =12kx22−x12=125×10310×10−22−5×10−22=18.75N−mTalk to our academic expert!
Similar Questions
Two similar springs P and Q have spring constants such that Kp > . They are stretched first by the same amount (case a), then by the same force (case b). The work done by the springs are related as, in case (a) and case (b), respectively.
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