Q.
A spring is stretched by 0.20 m, when a mass of 0.50 kg is suspended. When a mass of 0.25 kg is suspended, then its period of oscillation will be (g=10m/s2)
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a
0.328 sec
b
0.628 sec
c
0.137 sec
d
1.00 sec
answer is B.
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Detailed Solution
Force constant k=Fx=0.5×100.2=25 N/mNow T=2πmk=2π0.2525=0.628sec
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