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Q.

The spring and string shown in the figure are ideal and spring constant of  spring  is  100Nm−1. The coefficient of friction between 2m and surface is 0.8 and mass m of hanging block is 1kg. The system is released with spring in unstretched position. The maximum extension of spring in cm is __________

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answer is 8 CM.

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Detailed Solution

Let  x= extension in spring then Distance covered by m is  x1=2xLoss of P.E of m= gain of P.E of spring + work done  by friction m1g×x1=12kx2+f⋅x1×10×2x=12×100x2+0.8×2×10×x20x−16x=12×100x24x=12×100x2x=8100m=8cm
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The spring and string shown in the figure are ideal and spring constant of  spring  is  100Nm−1. The coefficient of friction between 2m and surface is 0.8 and mass m of hanging block is 1kg. The system is released with spring in unstretched position. The maximum extension of spring in cm is __________