Q.

A spring when stretched by 2 mm its potential energy becomes 4 J. If it is stretched by 10 mm, its potential energy is equal to

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a

4 J

b

54 J

c

415 J

d

None

answer is D.

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Detailed Solution

U=12kx2  if x becomes 5 times then energy will become 25 times i.e. 4×25=100 J
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Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
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