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Work

Question

A spring with spring constant k when stretched through 1 cm, the potential energy is U. If it is stretched by 4 cm. The potential energy will be n times. The value of n is

Moderate

Solution

Potential energy $U = \frac{1}{2} {kx}^{2}$
$∴ U \propto x^{2}$ [if k = constant]
If elongation made 4 times then potential energy will become 16 times.

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