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A square conducting loop of side length L carries a current I. The magnetic field at the center of the loop is
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a
independent of L
b
proportional to L
c
inversely proportional to L
d
linearly proportional to L
answer is C.
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Detailed Solution
Magnetic field at the centre due to either armB1=μ04π×I(L/2)sin45°+sin45° =μ04π×22ILB=4B1=4×μ04π×22IL i.e., B∝1LField at centre due to the four arms of the square
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