Q.

A square conducting loop of side length L carries a current I. The magnetic field at the center of the loop is

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a

independent of L

b

proportional to L

c

inversely proportional to L

d

linearly proportional to L

answer is C.

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Detailed Solution

Magnetic field at the centre due to either armB1=μ04π×I(L/2)sin45°+sin45° =μ04π×22ILB=4B1=4×μ04π×22IL  i.e.,   B∝1LField at centre due to the four arms of the square
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