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A square conducting loop of side length L carries a current I. The magnetic field at the center of the loop is

independent of L
proportional to L
inversely proportional to L
linearly proportional to L

detailed solution

Correct option is C

Magnetic field at the centre due to either armB1=μ04π×I(L/2)sin45°+sin45° =μ04π×22ILB=4B1=4×μ04π×22IL  i.e.,   B∝1LField at centre due to the four arms of the square

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