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Q.

A square conducting loop of side length L carries a current I. The magnetic field at the centre of the loop is

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a

independent of L

b

proportional to L2

c

inversely proportional to L

d

linearly proportional to L

answer is C.

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Detailed Solution

Magnetic field at the centre due to either armB= μ04π × IL/2 sin 450 + sin 450=μ04π × 22ILField at centre due to the four arms of the squareB=4B1 =4×μ04π × 22ILi.e., B ∝ 1L

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