A square conducting loop of side length L carries a current I. The magnetic field at the centre of the loop is
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a
independent of L
b
proportional to L2
c
inversely proportional to L
d
linearly proportional to L
answer is C.
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Detailed Solution
Magnetic field at the centre due to either armB= μ04π × IL/2 sin 450 + sin 450=μ04π × 22ILField at centre due to the four arms of the squareB=4B1 =4×μ04π × 22ILi.e., B ∝ 1L