A square frame ABCD, made of copper wire is made to move with a velocity V parallel to the diagonal DB in a uniform magnetic field of induction ‘B’ as shown in figure. Induced potential difference between points A and D is 2 volt. Then select the correct option.

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Induced potential difference in the loop is 4 volt

Induced potential difference between B and D is 22 volt.

Induced potential difference between A and C is 4 volt

Induced potential difference between A and C is 22 volt

answer is C.

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Detailed Solution

Component of V→ perpendicular to AD is V sin 45o. If l be the length of side of the square, then VA-VD=BlV sin45o.∴ BlV.sin45o=2⇒BlV=22 voltVelocity V→ is perpendicular to the diagonal AC.∴ VA−VC=BACV=B2lV=2BlV=2×22 volt⇒VA−VC=4 voltSince velocity V→ is parallel to the diagonal BD, VB-VD=0.

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