First slide
Motional EMF
Question

A square frame ABCD, made of copper wire is made to move with a velocity V parallel to the diagonal DB in a uniform magnetic field of induction ‘B’ as shown in figure. Induced potential difference between points A and D is 2 volt. Then select the correct option. 

Difficult
Solution

Component  of V perpendicular to AD is V sin 45o. If l be the length of side of the square, then VA-VD=BlV sin45o.

BlV.sin45o=2BlV=22volt

Velocity V is perpendicular to the diagonal AC.

VAVC=BACV=B2lV=2BlV=2×22volt

VAVC=4volt

Since velocity V is parallel to the diagonal BD, VB-VD=0.

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