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Q.

A square frame ABCD of side o and a long current carrying conductor PQ arc arranged as shown in fig.(7). If the frame moves towards right with avelocity ‘v’, the resultant induced e.m.f. in the loop will be

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a

μ0ia2v2πx(x+a)

b

μ0iav2πx

c

μ0iav2π(x+a)

d

μ0iav2πx(x+a)

answer is A.

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Detailed Solution

The induced e.m.f. in AD is given byeAD=μ0i2πxav Similarly, eBC=μ0i2π(x+a)av∴ Resultant e.m.f. = eAD -eBC or e=μ0 i a V2π1x−1x+a=μ0ia2v2πx(x+a)
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