Questions
A square frame ABCD of side o and a long current carrying conductor PQ arc arranged as shown in fig.(7). If the frame moves towards right with a
velocity ‘v’, the resultant induced e.m.f. in the loop will be
detailed solution
Correct option is A
The induced e.m.f. in AD is given byeAD=μ0i2πxav Similarly, eBC=μ0i2π(x+a)av∴ Resultant e.m.f. = eAD -eBC or e=μ0 i a V2π1x−1x+a=μ0ia2v2πx(x+a)Talk to our academic expert!
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A conductor rod AB moves parallel to X-axis in a uniform magnetic field, pointing in the positive X-direction. The end A of the rod gets
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