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Q.

A square loop ABCD of side a carrying current I is folded about an axis passing through its centre (y-axis). The two halves are inclined at angle 300 with xy plane as shown. -Find the magnetic fieid at origin. The origin coincides with the centre of loop.

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a

μ0I32πa

b

μ0I322πa

c

3μ0I22πa

d

6μ0Iπa

answer is D.

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Detailed Solution

Bnet  =  2Bhalf  cos θWhere  Bhalf = 12 4μ04πa Ia/2  cos450 +  cos 450=μ0I2πaSo     B=2 μ0I2πa  32  =  6μ0I πa
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