A square loop ABCD of side a carrying current I is folded about an axis passing through its centre (y-axis). The two halves are inclined at angle $$300$$ with xy plane as shown. $$-Find$$ the magnetic fieid at origin. The origin coincides with the centre of loop.

Question

Infinity Learn · Accepted Answer

Bnet  $$=$$  $$2Bhalf$$  $$cos$$ θWhere  Bhalf $$=$$ $$12$$ $$4$$μ$$04$$$$π$$a $$Ia/2$$  $$cos450$$ $$+$$  $$cos$$ $$450=$$μ$$0I2$$$$π$$aSo     $$B=2$$ μ$$0I2$$$$π$$a  $$32$$  $$=$$  $$6$$μ$$0I$$ πa

A square loop ABCD of side a carrying current I is folded about an axis passing through its centre (y-axis). The two halves are inclined at angle 30⁰ with xy plane as shown. -Find the magnetic fieid at origin. The origin coincides with the centre of loop.

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A square loop ABCD of side a carrying current I is folded about an axis passing through its centre (y-axis). The two halves are inclined at angle 300 with xy plane as shown. -Find the magnetic fieid at origin. The origin coincides with the centre of loop.

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A square loop ABCD of side a carrying current I is folded about an axis passing through its centre (y-axis). The two halves are inclined at angle 30⁰ with xy plane as shown. -Find the magnetic fieid at origin. The origin coincides with the centre of loop.