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A square loop of side 5 cm enters a magnetic field with 1 cms^-1. The front edge enters the magnetic field at t = 0 then which graph best depicts emf

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detailed solution

Correct option is C

When loop is entering in the field, magnetic flux (i.e. x) linked with the loop increases so induced emf in it is ε = Bvl=0.6×10−2×5×10−2=3×10−4V (Negative) When loop completely entered in the field (after 5 sec) flux linked with the loop remains constant so ε = 0.After 15 sec, loop begins to exit out, linked magnetic flux decreases so induced emf is ε = 3 x 10-4V (Positive).

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