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A square metallic wire loop of side 0.1 m and resistance of 1Ω is moved with a constant velocity in a magnetic field of 2 wb/m2 as shown in figure. The magnetic field is perpendicular to the plane of the loop, loop is connected to a network of resistances. What should be the velocity of loop so as to have a steady current of 1mA in loop

a
1 cm/sec
b
2 cm/sec
c
3 cm/sec
d
4 cm/sec

detailed solution

Correct option is B

Equivalent resistance of the given Wheatstone bridge circuit (balanced) is 3Ω so total resistance in circuit is  R=3+1=4Ω. The emf induced in the loop e=Bvl .So induced current  i=eR=BvlR   ⇒   10−3=2×v×(10×10−2)4⇒v=2cm/sec.

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