A square $$non-conducting$$ loop, $$20$$ cm, on a side is placed in a magnetic field. The center of side AB coincides with the center of magnetic field. The magnetic field is increasing at the rate of $$2$$ $$T/s$$. The potential difference between C and D is

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Infinity Learn · Accepted Answer

Perpendicular distance between CD and O is d $$=$$ $$20cm$$. Consider a small element at distance x of length dx.Induced electric field is tangential to the circle of radius $$r=d2+l2-x2$$.∫E→.dl→$$=AdBdt$$ ⇒$$E2$$$$π$$$$r=$$π$$r2dBdt$$ ⇒$$E=r2dBdt$$ Now,  △$$V=$$∫Ecosθdx ⇒△$$V=$$∫$$r2dBdt$$×dr×dx ⇒△$$V=d2dBdtlCD=0.22$$×$$2$$×$$0.2=0.04V=40mV$$

A square non-conducting loop, 20 cm, on a side is placed in a magnetic field. The center of side AB coincides with the center of magnetic field. The magnetic field is increasing at the rate of 2 T/s. The potential difference between C and D is

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