A square plate of 0.1 m side moves parallel to a second plate with a velocity of 0.1 m/s, both plates being immersed in water. If the viscous force is 0.002 N and the coefficient of viscosity is 0.001 poise, distance between the plates in m is

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0.1

0.05

0.005

0.0005

answer is D.

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Detailed Solution

A=(0.1)2=0.01m2η=0.01 Poise =0.001 decapoise (M.K.S. unit), dv=0.1m/s and F__=0.002NF=ηAdvdx∴dx=ηAdvF=0.001×0.01×0.10.002=0.0005m.

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