First slide

Viscous flow/Laminar flow

Question

A square plate of 0.1 m side moves parallel to a second plate with a velocity of 0.1 m/s, both plates being immersed in water. If the viscous force is 0.002 N and the coefficient of viscosity is 0.01 poise, distance between the plates in m is

Moderate

A

0.1
B

0.05
C

0.005
D

0.0005

Solution

$A = (0.1)^{2} = 0.01 m^{2}, η = 0.01 poise = 0.001 decapoise$
$(M.K.S. unit), d v = 0.1 m / s and F = 0.002 N$
$F = η A \frac{d v}{d x}$
$∴ d x = \frac{η A d v}{F} = \frac{0.001 \times 0.01 \times 0.1}{0.002} = 0.0005 m$

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