The square of the resultant of two forces 4 N and 3 N exceeds the square of the resultant of the two forces by 12, when they are mutually perpendicular. The angle between the vectors is

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answer is 2.

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Detailed Solution

θ1 = 900, resultant is R1θ2 = θ, resultant is R2 and R22 = R12 +12P2+Q2 +2PQcosθ = P2 +Q2+122PQcosθ = 12 ⇒ 2(4)(3)cosθ=12cosθ=1/2 ⇒θ=600

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