The square of the resultant of two forces 4 N and 3 N exceeds the square of the resultant of the two forces by 12, when they are mutually perpendicular. The angle between the vectors is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
answer is 2.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
θ1 = 900, resultant is R1θ2 = θ, resultant is R2 and R22 = R12 +12P2+Q2 +2PQcosθ = P2 +Q2+122PQcosθ = 12 ⇒ 2(4)(3)cosθ=12cosθ=1/2 ⇒θ=600
The square of the resultant of two forces 4 N and 3 N exceeds the square of the resultant of the two forces by 12, when they are mutually perpendicular. The angle between the vectors is