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A square of side a and uniform thickness is divided into four equal parts. If upper right part is removed, then find the coordinates of centre of mass of remaining part.

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a
(512a, 512a)
b
(712a, 712a)
c
(14a, 14a)
d
(13a, 13a)

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detailed solution

Correct option is A

Let mass of each part is m. Coordinates of their respective centre of masses are shown in figure.xcm = ma4+m3a4+ma4m+m+m = 5a12ycm = ma4+ma4+m3a4m+m+m = 5a12

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