Square of velocity and position graph of a particle is given, at point A slope is 45° then acceleration of particle at ,4 is :
4 m/s2
2 m/s2
1 m/s2
0.5 m/s2
Slope of v2−x graph= slope =dv2dx=2vdvdx=2a⇒ tan45∘=2a⇒a=12m/s2