In a standard meter bridge experiment, to measure the specific resistance of a wire the following data are found:- Length (L)=(1±.01)m measured by a meter scale Radius of wire =1mm±.01mm (measured by screw gauge).Resistance of wire (R)=(5±.01)ΩThe maximum possible error in the measurement of specific resistance is(You may use the formula:- :−ρ=πr2LR
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a
· 1μΩm
b
2μΩm
c
.5024μΩm
d
6024μΩm
answer is C.
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Detailed Solution
ρ=3⋅14×10−6×51 =15.7μ ohm metre. δρ=ρ2δrr+δLL+δRR ohm metre. =15⋅7μ2×.011+.011+.015 ohm metre =15.7μ[.02+.01+.002] ohm - metre =15.7×.032μΩm =.5024μΩm