Q.

In a standard meter bridge experiment, to measure the specific resistance of a wire the following data are found:- Length (L)=(1±.01)m measured by a meter scale Radius of wire =1mm±.01mm (measured by screw gauge).Resistance of wire (R)=(5±.01)ΩThe maximum possible error in the measurement of specific resistance is(You may use the formula:- :−ρ=πr2LR

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a

· 1μΩm

b

2μΩm

c

.5024μΩm

d

6024μΩm

answer is C.

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Detailed Solution

ρ=3⋅14×10−6×51 =15.7μ ohm metre.  δρ=ρ2δrr+δLL+δRR ohm metre.  =15⋅7μ2×.011+.011+.015 ohm metre  =15.7μ[.02+.01+.002] ohm - metre  =15.7×.032μΩm =.5024μΩm
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