Q.

In a standard YDSE apparatus a thin film μ=1.5,t=2.1μm is placed to front of upper slit. How far above or below the center point of the screen is nearest maxima located? Take D = 1m, d = 1 mm, λ=4500A0 .(Symbols have usual meaning)

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

1.5 mm

b

0.6 mm

c

0.15 mm

d

0.3 mm

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Shift of Central Bright due to insertion of slab,  x=Ddμ−1t ⇒x=2.1×10−6×(1.5-1)10−3 ⇒x=1.05×10−3=1.05 mm  Also, fringe width β=Dλd=1×4500×10−1010−3=45×10−5=0.45×10−3=0.45 mm   Distance between 2B and Mid point = 1.05 - 0.90 = 0.15 mmDistance between 3B and Mid point = 1.35 - 1.05 = 0.30 mmHence, Maxima nearest to Mid point is 2B. (i.e, 0.15mm)
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon