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Q.

A standing wave is maintained in a homogeneous string of cross-sectional area s and density ρ. It is formed by the super position of two waves travelling in opposite directions given by the equations  y1=asinωt−kx and  y2=2asinωt+kx. The total mechanical energy confined between the sections corresponding to the adjacent antinodes is

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a

3πsρω2a22k

b

πsρω2a22k

c

5πsρω2a22k

d

2πsρω2a22k

answer is C.

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Detailed Solution

Distance between two adjacent antinodes is λ2  or  πk, volume of string between two adjacent antinodes V=πks ∴ E=(V)u1+u2         Here, u is the energy density (energy per unit volume) which is equal to 12ρA2ω2∴     E=πks12ρa2ω2+12ρ2a2ω2=5πsρa2ω22k
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