A standing wave is maintained in a homogeneous string of cross-sectional area s and density ρ. It is formed by the super position of two waves travelling in opposite directions given by the equations y1=asinωt−kx and y2=2asinωt+kx. The total mechanical energy confined between the sections corresponding to the adjacent antinodes is
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a
3πsρω2a22k
b
πsρω2a22k
c
5πsρω2a22k
d
2πsρω2a22k
answer is C.
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Detailed Solution
Distance between two adjacent antinodes is λ2 or πk, volume of string between two adjacent antinodes V=πks ∴ E=(V)u1+u2 Here, u is the energy density (energy per unit volume) which is equal to 12ρA2ω2∴ E=πks12ρa2ω2+12ρ2a2ω2=5πsρa2ω22k