Q.

Standing waves are produced in a 10 m long stretched string. If the string vibrates in 5 segments and the wave velocity is 20 m/s, the frequency is

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a

2 Hz

b

4 Hz

c

5 Hz

d

10 Hz

answer is C.

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Detailed Solution

String vibrates in five segment so 52λ=l⇒λ=2l5Hence n=vλ=5×v2l=5×202×10=5Hz
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Standing waves are produced in a 10 m long stretched string. If the string vibrates in 5 segments and the wave velocity is 20 m/s, the frequency is