Questions
Standing waves are produced in a 10 m long stretched string. If the string vibrates in 5 segments and the wave velocity is 20 m/s, the frequency is
detailed solution
Correct option is C
String vibrates in five segment so 52λ=l⇒λ=2l5Hence n=vλ=5×v2l=5×202×10=5HzTalk to our academic expert!
Similar Questions
A wire having a linear density of 5 g/m is stretched between two rigid supports with a tension of 450 N. It is observed that the wire resonates at a frequency of 420 Hz. The next highest frequency at which the same wire resonates is 490 Hz. Find the length of the wire. (in m)
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