Q.
A star behaves like perfect Black body emitting radiant energy. The ratio of radiant energy emitted per sec by this star to that emitted by another star having 8 times the radius of the former but having Kelvin temperature one fourth of the former is
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a
1:4
b
1:8
c
4:1
d
1:16
answer is C.
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Detailed Solution
P=σAT4⇒P=σ4πR2T4∴P2P1=R2R12T2T14
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