Starting from rest, a body slides down a $$45$$° inclined plane in twice the time it takes to slide the same distance in the absence of friction. What is the coefficient of friction between the body and the inclined plane ?

Question

Infinity Learn · Accepted Answer

For a frictionless surface, o $$=g$$ $$sin$$ $$45$$° $$=$$ $$g/$$√$$2$$∴ $$l=12$$×$$g2$$×$$t22$$   …(1)In$$ presence of friction.$$a=g2$$−μ$$g2=g2(1$$−μ$$)∴ $$l=12$$×$$g2(1$$−μ$$)$$×$$t12$$   …(2)Dividing$$ eq. $$(2) by eq. (1), we $$get1=(1$$−μ$$)t12t22=(1$$−μ$$)2t22t22=(1$$−μ$$)$$×$$4$$ or $$(1$$−μ$$)=1/4$$  or  μ$$=3/4$$.

Starting from rest, a body slides down a 45° inclined plane in twice the time it takes to slide the same distance in the absence of friction. What is the coefficient of friction between the body and the inclined plane ?

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