First slide

Second law

Question

Starting from rest a 5 kg body gains a velocity of $\bar{v} = (3 \hat{i} + 4 \hat{j}) m / s$ , in 2.5 S. Then average force acting on the body is

Easy

A

5 N
B

3.5 N
C

2.5 N
D

10 N

Solution

$\begin{array}{l} \vec{a} = \frac{\vec{v} - 0}{t} = \frac{3 \hat{i} + 4 \hat{j}}{2 .5} m / s^{2} \\ \Rightarrow | \vec{a} | = 2 m / s^{2} \end{array} ∴ Average force = ma = 5 \times 2 N = 10 N$

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