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Q.

Starting from rest a 5 kg body gains a velocity of v¯=(3i^+4j^)m/s, in 2.5 S. Then average force acting on the body is

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a

5 N

b

3.5 N

c

2.5 N

d

10 N

answer is D.

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Detailed Solution

a→=v→−0t=3i^+4j^2.5m/s2⇒|a→|=2m/s2 ∴ Average force =ma=5×2N=10N
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Starting from rest a 5 kg body gains a velocity of v¯=(3i^+4j^)m/s, in 2.5 S. Then average force acting on the body is