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Starting with the same initial conditions, an ideal gas expands from volume V1 to V2 in three different ways. The work done by the gas is W1, if the process is isothermal W2, if isobaric and W3 , if adiabatic, then

a
W2>W1>W3
b
W2>W3>W1
c
W1>W2>W3
d
W1>W3>W2

detailed solution

Correct option is A

W = Area under ρ-V graphA2 > A1 > A3∴ W2>W1>W3

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