First slide
Simple hormonic motion
Question

Statement I: A small body of mass 0.1 kg is undergoing SHM of amplitude 1.0 m and period 0.2 s. The maximum value of the force acting on it is 98.7 N.
Statement II: Maximum force acting on it is given by F = 2r.

Moderate
Solution

The maximum force is given by

F = 2r

    = m×(2πT)2×r

     = 0.1(2π0.2)×1.0

      = 0.1×(10π)2 = 98.7 N

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