A stationary body of mass 3 kg explodes into three equal pieces. Two of the pieces fly off at right angles to each other, one with a velocity $2\widehat{\mathrm{i}}$ m/s and the other with a velocity $3\widehat{\mathrm{j}}$ m/s. If the explosion takes place in 10^-5 sec, the average force acting on the third piece in Newtons is:

• A

  $(2\widehat{\mathrm{i}}+3\widehat{\mathrm{j}}){10}^{-5}$

• B

  $-(2\widehat{\mathrm{i}}+3\widehat{\mathrm{j}}){10}^{+5}$

• C

  $(3\widehat{\mathrm{j}}-2\widehat{\mathrm{i}}){10}^{-5}$

• D

  $(2\widehat{\mathrm{j}}-2\widehat{\mathrm{i}}){10}^{-5}$