A stationary body of mass $$3kg$$ explodes into three equal pieces. Two of the pieces fly off at at right angles to each other, one with a $$velocity2i^$$ $$m/s$$ and the other with a velocity $$3j^$$ $$m/s$$. If the explosion takes place in $$10-5sec$$, the average force acting on the third piece in newton is

Question

A stationary body of mass $$3kg$$ explodes into three equal pieces. Two of the pieces fly off at at right angles to each other, one with a $$velocity2i^$$ $$m/s$$ and the other with a velocity $$3j^$$ $$m/s$$. If the explosion takes place in $$10-5sec$$, the average force acting on the third piece in newton is

Infinity Learn · Accepted Answer

according to conservation of linear momentum $$0$$ $$=m32i^+m32j^+m3v$$ $$m3v$$ $$=-m32i^+m32j^$$ force on third piece is $$m3vt$$ $$=-2i^+2j^$$ $$105$$

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A stationary body of mass 3kg explodes into three equal pieces. Two of the pieces fly off at at right angles to each other, one with a velocity2i^ m/s and the other with a velocity 3j^ m/s. If the explosion takes place in 10-5sec, the average force acting on the third piece in newton is

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