First slide

Bohr Model of the Hydrogen atom.

Question

In a stationary hydrogen atom, an electron jumps from n=2 to n=1, then linear momentum of the atom is

Moderate

A

$2 .84 \times 10^{- 28} kg . m / s$
B

$3 .48 \times 10^{- 26} kg . m / s$
C

$5 .44 \times 10^{- 27} kg . m / s$
D

$4 .21 \times 10^{- 27} kg . m / s$

Solution

Energy of emitted photon $= 13 .6 (1 - \frac{1}{2^{2}}) ev = 10 .2 ev$
$∴$ Momentum of the photon $= \frac{E}{c} = \frac{102 \times 1 .6 \times 10^{- 19}}{3 \times 10^{8}} kg - m / s$
$= 5 .44 \times 10^{- 27} kg - m / s$
By conservation of linear momentum, we conclude that momentum of the hydrogen atom
$= 5 .44 \times 10^{- 27} kg - m / s$

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