First slide

Motion in a plane

Question

A stationary man observes that the rain is falling vertically downward. When he starts running with a velocity of 12 km/h, he observes that the rain is falling at an angle $60^{0}$ with the vertical. The actual velocity of rain is

Moderate

Solution

$\begin{array}{l} \tan 60^{0} = \frac{v_{x}}{v_{y}} \\ \sqrt{3} = \frac{12}{v_{y}} \\ ∴ v_{y} = 4 \sqrt{3} k m / h \end{array}$

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