A stationary observer receives sound from two identical tuning forks, one of which approaches and the other one recedes with the same speed (much$$ less than the speed of $$sound). The observer hears $$2$$ $$beats/$$$$sec$$. The oscillation frequency of each tuning fork is $$f0$$ $$=$$ $$1400Hz$$ and the velocity of sound in air is $$350$$ $$m/s$$. The speed of each tuning fork is close to:

Question

A stationary observer receives sound from two identical tuning forks, one of which approaches and the other one recedes with the same speed (much$$ less than the speed of $$sound). The observer hears $$2$$ $$beats/$$$$sec$$. The oscillation frequency of each tuning fork is $$f0$$ $$=$$ $$1400Hz$$ and the velocity of sound in air is $$350$$ $$m/s$$. The speed of each tuning fork is close to:

Infinity Learn · Accepted Answer

$$Beat=Apparent$$ frequency due to source $$1$$ − Apparent frequency due to source $$2$$⇒Beat $$=$$ $$f0CC$$−V−$$f0CC+V=2$$             here $$C=speed$$ of sound⇒$$f0C2VC2$$−$$V2=2Since$$, V<

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