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A stationary particle explodes into three fragments. Momentum of two fragments are P→1=4i^+3j^kg−m/s and P→2=−i^+j^kg−m/s. Then magnitude of momentum of the third particle is ______

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a

43 kg−m/s

b

5 kg−m/s

c

32 kg−m/s

d

65 kg−m/s

answer is D.

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Detailed Solution

P→1 + P→2 + P→3 =0 ⇒ P→3 = −3i^+4j^ kg−m/s∴ P3=32+42 kg−ms=5 kg−m/s

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A stationary particle explodes into three fragments. Momentum of two fragments are P→1=4i^+3j^kg−m/s and P→2=−i^+j^kg−m/s. Then magnitude of momentum of the third particle is ______