Q.
A stationary person observes that rain is falling vertically down at 30 kmh-1. A cyclist is moving up on an inclined plane making an angle 30o with horizontal at 10 kmh-1. In which direction should the cyclist hold his umbrella to prevent himself from the rain?
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a
At an angle tan−1335 with inclined plane
b
At an angle tan−1335 with horizontal
c
At an angle tan−137with inclined plane
d
At an angle tan−137 with vertical
answer is A.
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Detailed Solution
v→r=−30j^,v→m=1032i^+102j^tanθ=5335=37⇒θ=tan−137 with vertical Angle of vr/m with inclined plane is 60∘−θ=βtanβ=tan60∘−θ =tan60∘−tanθ1+tan60∘tanθ =3−3/71+3⋅3/7=335⇒ β=tan−1335
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