Q.

In a stationary wave pattern that forms as a result of reflection of waves from an obstacle the ratio of the amplitude at an antinode and a node is  β =1.5 what percentage of the energy passes across the obstacle

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a

96%

b

4%

c

92%

d

8%

answer is A.

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Detailed Solution

Amplitude at antinodes a1+a2  and at nodes a1-a2   We have been given β =a1+a2a1-a2= 1.5solving a1a2= 5     i.e,  a2=a15   intensity of  the reflected wave I2=I125percentage of energy reflected  I125100I1=4  so percentage  of energy transmitted across the obstacle= 96
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