Q.
In a stationary wave pattern that forms as a result of reflection of waves from an obstacle the ratio of the amplitude at an antinode and a node is β =1.5 what percentage of the energy passes across the obstacle
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a
96%
b
4%
c
92%
d
8%
answer is A.
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Detailed Solution
Amplitude at antinodes a1+a2 and at nodes a1-a2 We have been given β =a1+a2a1-a2= 1.5solving a1a2= 5 i.e, a2=a15 intensity of the reflected wave I2=I125percentage of energy reflected I125100I1=4 so percentage of energy transmitted across the obstacle= 96
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