The stationary wave y=2a sin kx cos ωt in a closed organ pipe is the result of the superposition of y=a sin(ω t−kx) and
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a
y=−acos(ω t+kx)
b
y=−asin(ω t+kx)
c
y=asin(ω t+kx)
d
y=acos(ω t+kx)
answer is B.
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Detailed Solution
In closed organ pipe. If yincident=asin(ωt−kx)then yreflected=asin(ωt+kx+π)=−asin(ωt+kx)Superimposition of these two waves give the required stationary wave.