First slide

Stationary waves

Question

Stationary waves are set up in air column. Velocity of sound in air is 330 m/s and frequency is 165 Hz. Then distance between the nodes is

Easy

A

2 m
B

1 m
C

0.5 m
D

4 m

Solution

$v = 330 m / s; n = 165 Hz$ . Distance between two successive nodes = $\frac{λ}{2} = \frac{v}{2 n} = \frac{330}{2 \times 165} = 1 m$

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