In stationary waves, distance between a node and its nearest antinode is 20 cm. The phase difference between two particles having a separation of 60 cm will be

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Zero

π/2

3π/2

answer is D.

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Detailed Solution

λ4=20⇒λ= 80 cm, also Δφ=λ2π. Δx⇒Δφ=6080×2π=3π2

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