First slide

Stationary waves

Question

In stationary waves, distance between a node and its nearest antinode is 20 cm. The phase difference between two particles having a separation of 60 cm will be

Easy

A

Zero
B

$π / 2$
C

$π$
D

$3 π / 2$

Solution

$\frac{λ}{4} = 20 \Rightarrow λ = 80 cm$ , also $Δφ = \frac{λ}{2 π} . Δx$
$\Rightarrow Δφ = \frac{60}{80} \times 2 π = \frac{3 π}{2}$

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