A steady current is flowing in a circular coil of radius R, made up of a thin conducting wire. The magnetic field at the center of the loop is BL. Now, a circular loop of radius R/n is made from the same wire without changing its length, by unfolding and refolding the loop, and the same current is passed through it. If new magnetic field at the center of the coil is BC, then the ratio BL/BC, is
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a
1: n2
b
n1/2
c
n: 1
d
none of these
answer is A.
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Detailed Solution
BL=μ0I2R If the radius is R/n; the number of turns will be n BC=nμ0I2(R/n)=n2μ0I2R Hence, BLBC=1n2