In the steady state, the energy stored in the capacitor is :
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a
12CE1+E22
b
12CE1−E22
c
12CE1R1+E1R2r1+r2+R1+R22
d
12CE2+E1R1r1+R1+R22
answer is B.
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Detailed Solution
When the capacitor plate acquire full cahrge 0 q , there will be no current in the capacitor arm. Applying Kirchhoff’s second law to the current carrying circuitiR1+R2=E1−ir1 or i=E1r1+R1+R2Now Va−Vb=−iR1=−E1R1r1+R1+R2and VC=q0C=E2+iR1=E2+E1R1r1+R1+R2Now energy stored in the capacitorU=12CVc2;=12CE2+E1R1r1+R1+R22