In steady state find the current through branch containing the ideal inductor and voltage across capacitor.
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a
E9R A, E2V
b
E3RA,E3V
c
E2RA,E2V
d
E4R A,E3V
answer is C.
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Detailed Solution
at steady state inductor will be a conductor of zero resistance. so both the resistances of 2R will be short circuited and total resistance of the circuit will be 2R and current is E2R potential across the capacitance is iR i.e, E2